Let’s look at finding the inverse of y=log(x) algebraically. First, recall that y=log(x) is shorthand for y=log_{10}(x).

Step 1: Swap x and y. Now we have x=log_{10}(y).

Step 2: Transform the log equation into exponential form. 10^{x}=y

Step 3: Replace y with the inverse notation of f^{-1}(x). Thus, f^{-1}(x)=10^{x}

Try a more challenging one on your own, such as f(x)=log_{2}(x+3)